Among ten applicants for an open position,six are women and four are men. Suppos

Question

Among ten applicants for an open position,six are women and four are men. Suppose that three applicants are randomly selected for final interviews. Find the probability distribution for X, the number of female applicants among the final three. Among ten applicants for an open position,six are women and four are men. Suppose that three applicants are randomly selected for final interviews. Find the probability distribution for X, the number of female applicants among the final three. Among ten applicants for an open position,six are women and four are men. Suppose that three applicants are randomly selected for final interviews. Find the probability distribution for X, the number of female applicants among the final three.

Explanation / Answer

You want to find the distribution so you need to find out the chance of 0, 1, 2, and 3 females being chosen, so if you fill out a tree with all the possible outcomes like this mmm fmm mfm mmf ffm fmf mff fff ok now theres 10 total so theres a .60 chance of picking female and .40 chance of picking male. if you then take those values and plug them into each case you can get the probability of that outcome ex mff = .4x.6x.6 = .14 ok so after you crank out the numbers just add the cases with the same outcome ex mff+fmf+ffm=the probability of one woman and thats it you should have the outcome for all possibilities hope this helps

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