x x P(x) 0 .32 1 .35 2 .18 3 .08 4 .04 5 .02 6 .01 I d0o not uderstand this ques

Question

x x P(x) 0 .32 1 .35 2 .18 3 .08 4 .04 5 .02 6 .01 I d0o not uderstand this question at all and it is on my final exam.

The manager of a large computer network has developed the following probability distribution of the number of interruptions per day:
a. Find the mean b. Find the standard deviation c. P(at most 2 interuptions) d. P(more that 4 interruptions)

I d0o not uderstand this question at all and it is on my final exam.

The manager of a large computer network has developed the following probability distribution of the number of interruptions per day:
a. Find the mean b. Find the standard deviation c. P(at most 2 interuptions) d. P(more that 4 interruptions)

x P(x) 0 .32 1 .35 2 .18 3 .08 4 .04 5 .02 6 .01

Explanation / Answer

=0.03.

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