Golf Averages - A study of 35 golfers showed that theiraverage score on a partic

Question

Golf Averages - A study of 35 golfers showed that theiraverage score on a particular course was 92. The standarddeviation of the sample is 5.    a. Find the best point estimate of themean.    b. Find the 95% confidence interval of themean score for all golfers.    c. Find the 95% confidence interval ofthe mean score if a sample of 60 golfers is used instead of asample of 35    d. Which interval is smaller? ExplainWhy Golf Averages - A study of 35 golfers showed that theiraverage score on a particular course was 92. The standarddeviation of the sample is 5.    a. Find the best point estimate of themean.    b. Find the 95% confidence interval of themean score for all golfers.    c. Find the 95% confidence interval ofthe mean score if a sample of 60 golfers is used instead of asample of 35    d. Which interval is smaller? ExplainWhy

Explanation / Answer

Given xbar=92, s=5, n=35 (a) mean= 92 (b) =0.05, |Z(0.025)|=1.96 (check normal table) The 95% CI is xbar ± Z*s/n --> 92 ± 1.96*5/sqrt(35) --> (90.34, 93.66) (c) The 95% CI is xbar ± Z*s/n --> 92 ± 1.96*5/sqrt(60) --> (90.73,   93.27) (d) n=60>35

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