I do have answer fot this but they do not provide every singlestep so could you
ID: 2955099 • Letter: I
Question
I do have answer fot this but they do not provide every singlestep so could you explain step by step.. thank you in advance...a random sample of 300 shoppers at a supermarket incluides 204who regularly use cents off coupons. construct a 98% confidenceinterval for the probability that any one shopper at thesupermarket, selected at a random, will regularly use cents offcoupons I do have answer fot this but they do not provide every singlestep so could you explain step by step.. thank you in advance...
a random sample of 300 shoppers at a supermarket incluides 204who regularly use cents off coupons. construct a 98% confidenceinterval for the probability that any one shopper at thesupermarket, selected at a random, will regularly use cents offcoupons
Explanation / Answer
Given n=300, p=204/300=0.68 =0.02, |Z(0.01)|=2.326 (check normal table) The 98% CI is p ± Z*p*(1-p)/n --> 0.68 ± 2.326*sqrt(0.68*(1-0.68)/300) --> (0.617, 0.743)
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