c. State the decisionrule. d. Compute the value of the teststatistic. e. Find th
ID: 2955057 • Letter: C
Question
c. State the decisionrule.
d. Compute the value of the teststatistic.
e. Find the p-value
CherryBerry Soda, Inc. claims that 15 percent of thepopulation can identify its products. In efforts to boosttheir identity, CherryBerry employs a famous spokesperson toadvertise. A survey is then taken to assess the results ofthe ad campaign. The results show that 17 percent of the 1000respondents can identify CherryBerry products. Has theadvertising campaign increased product identity or is thedifference due to chance? Use the 0.10 significancelevel.
µ (populationmean): _______
(population standarddeviation): _______
X (samplemean): _______
s (sample standarddeviation): _______
(significancelevel): _______
(populationproportion): _______
p (sampleproportion): _______
a. State the null andalternate hypotheses.
H0: __________________
H1:__________________
b. Find the critical value
c. State the decision rule.
d. Compute the value of the teststatistic.
e. Find the p-value
f. What is your decision regarding the nullhypothesis? Interpret the result.
Explanation / Answer
c. State the decisionrule.
If Z>1.645, we reject Ho.
d. Compute the value of the teststatistic.
Z=(xbar-)/(s/n)
=(20.8-20)/(3.7/sqrt(40))
= 1.37
e. Find the p-value
P(Z>1.37)= 0.0853 (checknormal table)
a. State the null andalternate hypotheses.
H0: __p=0.15________________
H1: __p not equal0.15________________
b. Find the critical value
Given =0.1, |Z(0.05)|=1.645 (check normal table)
So the critical value is -1.645 or 1.645
c. State the decision rule.
If Z<-1.645 or Z>1.645, we rejectHo.
d. Compute the value of the teststatistic.
Z=(phat-p)/p*(1-p)/n
=(0.17-0.15)/sqrt(0.15*(1-0.15)/1000)
=1.77
2*P(Z<-1.77)= 0.0767 (check normal table)
f. What is your decision regarding the nullhypothesis? Interpret the result.
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