With a perfectly balanced roulette wheel, in the long run, rednumbers should tur

Question

With a perfectly balanced roulette wheel, in the long run, rednumbers should turn up 18 times in 38. To test its wheel, onecasino records the result of 3,800 plays, finding 1,890 rednumbers. Is that too many reds? Or chance variation? * The null says that the percentage of reds in the box is ___.The alternative says that the percentage of reds in the box is ___.Fill in the blanks. * Compute z and P. * Were there too many reds? With a perfectly balanced roulette wheel, in the long run, rednumbers should turn up 18 times in 38. To test its wheel, onecasino records the result of 3,800 plays, finding 1,890 rednumbers. Is that too many reds? Or chance variation? * The null says that the percentage of reds in the box is ___.The alternative says that the percentage of reds in the box is ___.Fill in the blanks. * Compute z and P. * Were there too many reds?

Explanation / Answer

Null hypothesis: The probability of red is 18/38. The difference that youobserved is due to chance. Alternative hypothesis: The probability of red of greater than 18/38. The differencethat you observed is real and not due to chance. Observed proportion is 1890/3800 Expected proportion is p =18/38 n = sample size = 3800 SE = sqrt[p * (1-p) / n] Z = (observed proportion - expected propotion)/SE After that, compute the area to the right of the z score.Remember that the FPP text gives a middle area. This is a 1-tailed test, because we want to know if there aretoo many reds. I'm purposely leaving out the numerical calculations, so youhave the opportunity to fill them in. Hope this helps, Mike

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