The conductivity of glass: How well materials conduct heatmatters when designing
ID: 2954674 • Letter: T
Question
The conductivity of glass: How well materials conduct heatmatters when designing houses, for example. Conductivity ismeasured in terms of watts of heat power transmitted per squaremeter of surface per degree Celsius of temperature difference onthe two sides ofthe material. In these units, glass hasconductivity about 1. The National Institute of Standard andTechnology (NIST) provides data on properties of materials. Here are 11 NIST measurement of the heat conductivity of aparticular type of glass:1.11 1.07 1.11 1.07 1.12 1.08 1.08 1.18 1.18 1.18 1.12 (a.) We can consider this an SRS of all specimens of glass ofthis type. Make a stemplot. Is there any sign of majordeviation from Normality? (b.) Give a 95% confidence interval for the meanconductivity. (c.) Is there significant evidence at the 5% level that themean conductivity of this type of glass is not 1? The conductivity of glass: How well materials conduct heatmatters when designing houses, for example. Conductivity ismeasured in terms of watts of heat power transmitted per squaremeter of surface per degree Celsius of temperature difference onthe two sides ofthe material. In these units, glass hasconductivity about 1. The National Institute of Standard andTechnology (NIST) provides data on properties of materials. Here are 11 NIST measurement of the heat conductivity of aparticular type of glass:1.11 1.07 1.11 1.07 1.12 1.08 1.08 1.18 1.18 1.18 1.12 (a.) We can consider this an SRS of all specimens of glass ofthis type. Make a stemplot. Is there any sign of majordeviation from Normality? (b.) Give a 95% confidence interval for the meanconductivity. (c.) Is there significant evidence at the 5% level that themean conductivity of this type of glass is not 1?Explanation / Answer
(a) The stemplot is below. The decimal point is 1 digit(s) to the left of the | 10 | 7788 11 | 1122 11 | 888 There is no sign of major deviation from Normality (b) xbar= 1.118, s=0.04, n=11 =0.05, t(0.025, df=n-1=10)=2.228 (check student t table) The 95% CI is xbar ± t*s/n --> 1.118 ± 2.228 *0.04/sqrt(11) --> (1.091, 1.145) (c) Since the interval based on (b) is not included 0, there is nosignificant evidence at the 5% level that the mean conductivity ofthis type of glass is not 1 (c.) Is there significant evidence at the 5% level that the meanconductivity of this type of glass is not 1? (c)
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