lower limit 1 upper limit 2 moe 3 Solution (a) n=49, xbar=37.5, =8 =0.2, Z(0.1)=
ID: 2954577 • Letter: L
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lower limit 1 upper limit 2 moe 3Explanation / Answer
(a) n=49, xbar=37.5, =8 =0.2, Z(0.1)=1.282 (check normal table) The 80% CI is xbar ± Z*/n --> 37.5 ± 1.282*8/sqrt(49) --> (36.03, 38.97) The margin of error is /n = 8/sqrt(49) = 1.14 ------------------------------------------------------------------------------------------------------------------------------ (b)n is large thedistribution of weights is normal ----------------------------------------------------------------------------------------------------------------------------- (c) 80% of the intervalscreated using this method will contain the true average bloodplasma volume in male firefighters. ------------------------------------------------------------------------------------------------------------------------------ (d) Given E = 2.30 =0.2, Z(0.1)=1.282 (check normal table) n=(Z*/E)^2 = (1.282*8/2.3)^2 = 19.88 Take n=20
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