Suppose that the life span of a calculator has a normaldistribution with a mean
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Suppose that the life span of a calculator has a normaldistribution with a mean of 60 months and a standard deviation of 8months. The probability that the calculator will work properly forat least 74 months is about: a) .9599 b) 1.75 c) .0401 d) .0359 e) .7500 Will rate lifesaver for a good explanation and answer.Thanks! Suppose that the life span of a calculator has a normaldistribution with a mean of 60 months and a standard deviation of 8months. The probability that the calculator will work properly forat least 74 months is about: a) .9599 b) 1.75 c) .0401 d) .0359 e) .7500 Will rate lifesaver for a good explanation and answer.Thanks!Explanation / Answer
The standard deviation is kind of the amount of variability inwhat statisticians call normaldistribution of data.
A normal distribution of data means that most items are close tothe "average," or last around the 60 months mark in this case whilerelatively few tend to one extreme or the other, breakingearly or lasting a long time.
Let's say you are buying a caluclator, for most people, it willlast 5 years, but you can graph a picture showing that some lastlonger.
When you find out how much the standard deviation is, you canlook on the graph and see how many people had cacluators thatlasted exatly average (0 standard deviations), more than average(positive SD) or less (negtive SD).
Look at the table and you can see, base on your number. 14months is almost 2 standard deviations HIGHER, lucky you!
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