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Olive Oil Low Medium High Total Colon Cancer 398 397 430 1225 Rectal Cancer 250

ID: 2952301 • Letter: O

Question

Olive Oil Low Medium High Total Colon Cancer 398 397 430 1225 Rectal Cancer 250 241 237 728 Control Group 1368 1377 1409 4154 Question: Cancer of the colon and rectum is less common in theMediterranean region than in other Western countries. TheMediterranean diet contains little animal fat and lots of oliveoil. Italian researchers compared 1,953 patients with colon orrectal cancer with a control group of 4,154 patients admitted tothe same hospitals for unrelated reasons. They estimatedconsumption of various foods from a detailed interview, thendivided the patients into three groups according to theirconsumption of olive oil. The table presents some of the data. Theresearchers conjectured that high olive oil consumption would bemore common among patients without cancer than among patients withcolon cancer or rectal cancer. What does the data say? Thank youvery much. Olive Oil Low Medium High Total Colon Cancer 398 397 430 1225 Rectal Cancer 250 241 237 728 Control Group 1368 1377 1409 4154 Question: Cancer of the colon and rectum is less common in theMediterranean region than in other Western countries. TheMediterranean diet contains little animal fat and lots of oliveoil. Italian researchers compared 1,953 patients with colon orrectal cancer with a control group of 4,154 patients admitted tothe same hospitals for unrelated reasons. They estimatedconsumption of various foods from a detailed interview, thendivided the patients into three groups according to theirconsumption of olive oil. The table presents some of the data. Theresearchers conjectured that high olive oil consumption would bemore common among patients without cancer than among patients withcolon cancer or rectal cancer. What does the data say? Thank youvery much. Olive Oil Low Medium High Total Colon Cancer 398 397 430 1225 Rectal Cancer 250 241 237 728 Control Group 1368 1377 1409 4154

Explanation / Answer

p = (p1 * n1 +p2 * n2) / (n1 +n2)

SE = sqrt{ p * ( 1 - p ) * [ (1/n1) + (1/n2)] }

z = (p1 - p2) / SE

p1 is the sample proportion of canceramong low/mid oil, p2 is the sample proportion ofcancer among high oil,

P-value is the probability that the z-score is less than? Use your table for your desired % in the tail

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