a) A group of 3 girls and 5 boys. How many ways can we line upthe 8 people so th

Question

a) A group of 3 girls and 5 boys. How many ways can we line upthe 8 people so that the girls are together and the boys aretogether? b) A legal firm has 6 lawers and 3 new cases. How many wayscan two lawers be assigned to each case if no lawer workson more than one case? a) A group of 3 girls and 5 boys. How many ways can we line upthe 8 people so that the girls are together and the boys aretogether? b) A legal firm has 6 lawers and 3 new cases. How many wayscan two lawers be assigned to each case if no lawer workson more than one case?

Explanation / Answer

a) If we place the girls in the first 3 seats and the boys inthe last 5 seats, we would have: 3*2*1*5*4*3*2*1 = 720 possibilities However, we could have placed the boys first and then thegirls so there's another 720 possibilities. Therefore, the total number of ways of placing them in theseats so that all the same sex seat together is 720 + 720 =1440 b) First pick two lawyers from the 6 for case A. This is a combination: C(6,2) Now from the remaining 4 pick 2 for caseB     C(4,2) The last two get picked for case C   C(2,2) Therefore, there are C(6,2)*C(4,2)*C(2,2) = 90possibilities

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.