The ratings for “driving distance off the tee” forthe top 10 golfers on the PGA
ID: 2951156 • Letter: T
Question
The ratings for “driving distance off the tee” forthe top 10 golfers on the PGA Tour are as follows:
Value (yards)
1
1
318.90
2
2
315.20
3
3
310.70
4
4
308.50
5
6
308.40
6
5
308.30
7
10
304.30
The Question:
How would you compute the probability, for any given drive onany given hole in any given tournament of the followingprobabilities for Tiger Woods, currently rated the Number Oneplayer in the world:
Note: Let D = the event “a given drive”
I am NOTlooking for specific probability numbers – I want to knowhow
you would compute them and what additional data you might needto
make the computation using the methodology you suggest.
a) P(D = 310 yards) = ? How would you determine thisprobability? What assumptions did you make?
b) P(300 < D < 320) = ? How would youdetermine this probability? What
assumptions did you make?
c) P(300 < D < 320) = ? Howwould you determine this probability? What assumptions didyou make?
Value (yards)
1
1
318.90
2
2
315.20
3
3
310.70
4
4
308.50
5
6
308.40
6
5
308.30
7
10
304.30
Explanation / Answer
one way would be to assume the distribution of the lengths of TigerWoods shots is a normal distribution . You would need the standard deviation of the distribution oflengths of tiger Woods shots and work with z tables. Sine the normal is continuous P(D=310)=0 and same reason band c would have the same answer. To work P(300Related Questions
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