Question Consider a reddish star with a temperature of 3820 K and a radius of 4.

Question

Question Consider a reddish star with a temperature of 3820 K and a radius of 4.07 x105 km. The star is a perfect black body with an emissivity of exactly 1. Part 1) Assuming radiation is the only method by which this star loses heat, what is the rate of heat loss from the star? Part 2) If the temperature of the star was doubled, but everything else remained constant, what would be the new power output of the star? Part 3) In reality, the radius and temperature of a star are not independent. Assume all main sequence stars have the same density. The mass and temperature of a star are related by constant. If you double the temperature of the star in part 1) and take the changing mass into account, what is the power output now? 4

Explanation / Answer

part 1) 2.512x10^22, formula of stefan- bolzmann equation; E = ?’?T4

E = total flux (W/m2), ?’ = effective emissivity , ? is a Stefan-Boltzmann constant and T = temperature in Kelvin (K)

? =5.6703 10-8 (W/m2K4) .A =area of sphere=4*pi*R^2.

part 2) 16x ans of Part 1=======>4.019x10^23

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