Derek Lee of the Chicago Cubs had the highest batting average inthe 2005 MLB sea
ID: 2950297 • Letter: D
Question
Derek Lee of the Chicago Cubs had the highest batting average inthe 2005 MLB season.His average was .355. So assume the probability of getting a hit is.355 for each time he
batted. In a particular game assume he batted three times. Let X =# of hits that Derrek
Lee got in that game.
Hint: the probability of getting a purple marble is .355, withreplacement, in 3 draws…
a. Determine the probability distribution for X.
b. Calculate the mean of X.
c. What is the probability of getting at least one hits?
Explanation / Answer
Product
0
.4431
.4878
.1341
x Probability (using binomial formulas)Product
0 C(3,0)(.355)0(.645)3˜ .26830
1 C(3,1)(.355)1(.645)2˜ .4431.4431
2 C(3,2)(.355)2(.645)1˜ .2439.4878
3 C(3,3)(.355)3(.645)0˜ .0447.1341
= 1 E[x]= 1.065 hitsRelated Questions
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