four part question view homeworlk d 13&flushed-false;&icld-5049662;&back-DoAssig
ID: 2949748 • Letter: F
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four part question
view homeworlk d 13&flushed-false;&icld-5049662;&back-DoAssignments.aspx; Playertomework.aspx?homeworkld-487013 Apps Bookmarks icola Waisome crooks 720/18 12-17PM MAT-240-X6831 Applied Statistics 18EW6 Save Homework: 3-2 MyStatLab: Module Three Problem Set HW Score: 8164%, 5307 of 65 pts 11 of 14 (14 complete) ? Score: 2.4 of 6 pts Question Help 9.2.30 A nutitionist wants to determine how much time nationally people spend eating and drinking Suppose for a random sample of 1097 people age 15 or older, the mean amount of time spent eatihg or drinking per day is 1.27 hours with a slandard deviation of 0.58 hour. Complete parts (a) through (d) below (e) A histogram of time spent eating and drinking each day is skewed right. Use this result to explain why a large samp O A. The distribution of the sample mean wil always be approximately normal O B. Since the distribution of time spent eating and drinking each day is not normally distributed (skewed right), the sample must be large so that the distribution of the sample mean will be approximately normal le size is needed to construct a confidence interval for the mean time spent eating and drinking each day C. The distribution of the sample mean will never be approximately normal O D. Since the distribution of time spent eating and drinking each day is normally distributed, the sample must be large so that the distribution of the sample mean will be approximately normal Cick to select your answer and then click Check Answer aining Check Answer 8311:17 AM Friday d?7/20/2018 ?Explanation / Answer
Here as sample size is 1097 so we will used CLT
Regardless of the population
distribution model, as the sample size increases,
the sample mean tends to be normal.
so option B is correct .
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