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flights Solved: At a (--) a cards are Quiz: Chapter 6 Quiz This Question: 1 pt (

ID: 2948765 • Letter: F

Question

flights Solved: At a (--) a cards are Quiz: Chapter 6 Quiz This Question: 1 pt (b) Find and interpret the probability that exactly 17 flights are on time. (c) Find and interpret the probability that fewer than 17 fights are on time. (d) Find and interpret the probability that at least 17 fights are on time. (e) Find and interpret the probability that between 15 and 17 flights, inclusive, are on time (a) identify the statements that explain why this is a binomial experiment Select all that apply A. The probability of success is the same for each trial of the experiment Each trial depends on the previous trial. There are two mutually exclusive outcomes, success or failure B. C. D. The experiment is E. F. There are three mutually exclusive possibly outcomes, arriving on-time, armiving early, and arriving late G. The experiment is performed until a desired number of successes is reached a fixed number of times The trials are independent. (b) The probability that exactly 17 flights are on time is Round to four decimal places as needed.) Interpret the probability (Round to the nearest whole number as needed.) (c) The probability that fewer than 17 flights are on time is Round to four decimal places as needed.,)

Explanation / Answer

a)

Answer is A) C) E)

b)
n = 24, p = 0.85

As per binomial distribution,
P(X=r) = nCr * p^r * (1-p)^(n-r)

P(x =17) = 24C17 * 0.85^17 * (1-0.85)^7
= 0.0373


c)

P(x < 17) = 0.0199

By using excel: =BINOM.DIST(16,24,0.85,TRUE)


d)

P(x >=17) = 1- P(x <=16)
By using excel: =BINOM.DIST(16,24,0.85,TRUE)
= 1 - 0.0199

= 0.9801


e)
P(x = 15) = 24C15 * 0.85^15 * (1-0.85)^9
= 0.0044

P(x = 16) = 24C16 * 0.85^16 * (1-0.85)^8
= 0.014

P(x <= 17) = 24C17 * 0.85^17 * (1-0.85)^7
= 0.0373

P(x =15) + P(x =16) + P(X = 17) = 0.0044 + 0.014 + 0.0373 = 0.0557

In 100 trials, it is expected about 100*0.0557 = 5.57 ~ 6.

About 6 times