In a survey of 108 people 703 people said they voted in a re presidental lection

Question

In a survey of 108 people 703 people said they voted in a re presidental lection Voting reoxeds show that 62% of eligible voters a allydd vole Given that 62% ol eligible voters actual y did vote a find the probablity that among 1085 'andor hy select d les at last T03 actually did te bl what do the res its from part (a) suggest? (a) PoX 2 703)-(Round to four decimal places as noodod) (b) What does the result from part (a) suggest? Some people are being less than honest because pex2 703) is at least 1% People are being honest because the probability of p(xz 703)ls at least 1% o A. O B. D C Some people are being less than honest becuse Pc3 703) is less than 5% ?D. People are being honest because the probabaty of P(x2 703) is leas than 5%

Explanation / Answer

Ans:

a) sample proportion=703/1085=0.6479

z=(0.6479-0.62)/sqrt(0.62*(1-0.62)/1085)

z=1.895

P(z>=1.895)=0.0290

b)Option C is correct,as P(x>=703)=0.0209,which is unusual event,as probability of the event is less than 0.05

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