Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A student was asked to find a 98% confidence interval for the proportion of stud

ID: 2948145 • Letter: A

Question

A student was asked to find a 98% confidence interval for the proportion of students who take notes using data from a random sample of size n = 86. Which of the following is a correct interpretation of the interval 0.12 < p < 0.28?

Check all that are correct.

The proprtion of all students who take notes is between 0.12 and 0.28, 98% of the time.

There is a 98% chance that the proportion of notetakers in a sample of 86 students will be between 0.12 and 0.28.

There is a 98% chance that the proportion of the population is between 0.12 and 0.28.

With 98% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.12 and 0.28.

With 98% confidence, the proportion of all students who take notes is between 0.12 and 0.28.

I have chosen the first "The proportion of all students who take notes is between 0.12 and 0.28, 98% of the time" and " With 98% confidence, the proportion of all students who take notes is between 0.12 and 0.28." The question is partly correct. Thanks for your help.

Explanation / Answer

A student was asked to find a 98% confidence interval for the proportion of students who take notes using data from a random sample of size n = 86. Therefore a correct interpretation of the interval 0.12 < p < 0.28 is,

Answer :- the correct answer is,

With 98% confidence, the proportion of all students who take notes is between 0.12 and 0.28.