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onld-14äflushed fabe&cld-; 5049577&back; D CSecure App DPL Web Portal facebockMa MAT-240-X6801 Applied Statistics 18EW6 nded G Google Wectren mSNHU VeeAcountSpectum Homework: 2-2 MyStatlab: Module Two Problem Set Score: 2 of 5 pts 15 of 15 (15 complete) 8.2.11 Suppose a simple random sample of sine n 75 is obtained om a population whose sice i N 25 000 and whose population proportion with a speciled charachorisic b p- Not normal because n s0 05N and 1-pa 1 B Appro mately na because n s0OSN andap(1-p)210 pproxmely normal because n s0 0SN and pl1-p) D. Not normal because asoo5N and rer-e-?? Determine the mean of the sampling distbfp 06 (Round to one decimal place as needed) Detemine the standard deviation of the sampling dbution of Round to slx decimal places as eeded) anwerbox and then cick Check Anwer 2

Explanation / Answer

Solution:- Given that p = 0.6, n = 75 q = 1-p = 0.4

Mean = p = 0.6

Standard deviation = sqrt(p*q/n) = sqrt(0.6*0.4/75) = 0.056569

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