??1?12?11tiall2ej | AaBbceDdEe AaBbccDdEe AaBbCcD AaBbCcDdi A | | Normal NoSpaci

Question

??1?12?11tiall2ej | AaBbceDdEe AaBbccDdEe AaBbCcD AaBbCcDdi A | | Normal NoSpacing Heading 1 Heading 2 Part 3-Chapter 15 The Manell Perfume Company is at it again trying to make a perfume that fits multiple age groups But this time they are evaluating a new scent called "Kcazy Kitty. They evaluate it on younger and older women. Each sampled woman will be asked to smell "Krazx Kitty" and indicate whether they like the fragrance enough to purchase a bottle. A random sample of 300 women between 20 to 30 and 320 women between 50 and 60 were evaluated. Results revealed that 200 younger and 230 older women liked the fragrance. Is there significant evidence to suggest that there is a difference in proportion between and 1. State the Null and Alternate: n older and younger woman who would purchase "Krazx Kitty"? (alpha 0.05) 2. State the level of significance: 3. State the Test Statistic: 4. State the Decision Rule Perform the Calculation-Make the decision 6. interpret the result 1 Pages: 5 of 11 Words 0 of 1029

Explanation / Answer

1)
H0 ; p1 = p2
Ha : p1 not equals to p2

2)
Level of significance = 0.05

3)

p1 = 230/320 = 0.7188 , n1 = 320
p2 = 200/300 = 0.6667, n2 = 300

p = (p1 * n1 + p2 * n2) / (n1 + n2)
= (0.7188 * 320 + 0.6667 * 300)/(320 + 300)
= 0.6936

SE = sqrt{ p * ( 1 - p ) * [ (1/n1) + (1/n2) ] }
= sqrt(0.6936 *(1-0.6936) *((1/320) + ( 1/300)))
= 0.0370

z = ( p1 -p2)/SE
= ( 0.7188 - 0.6667)/0.0370
= 1.4081

5)
p value = 0.1591
Do not reject the null hypothesis

6)
There is not sufficient evidence to support the claim

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.