Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq

Question

Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents ir two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. EB Click the icon to view the data table of strontium-90 amounts. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from aty #2. More Into The test statistic is (Round to two decimal places as The P-value is[ ]. (Round to three deomal places as ne -City #2 City #1 103 State the conclusion for the test 100 121 110 101 104 213 f strontium-90 from city #1 residents is greater. trontium-90 from aty #1 residents is greater. O A. Fail to reject the nul hypothesis. There is sufficien 0 B. Reject the null hypothesis. There is not sufficient ° C. Fail to reject the null hypothesis. There is not O D. Reject the null hypothesis. There is sufficient evid 107 110 of strontium-90 from city #1 residents is geater. tium-90 from city #1 residents is greater 100 291 145 136 133 101 Print Done Click to select your answer(s). e to search

Explanation / Answer

Hypothesis:

H0 : mu1 = mu2

Ha : mu1 > mu2

test statistics:

t = ( x1 -x2)/sqrt(s1^2/n1 +s2^2/n2)

= (147 - 113)/sqrt(74.8514^2/12 + 36.4417^2/12)

= 1.41

p value = .0924

Option C)

103 117

86 64

121 100

110 85

101 83

104 107

213 110

100 111

290 136

100 133

291 101

145 209

If is there any changes in number please let me know

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