1. (4 points, 0.5 each) You have been observing the local Liberal Party in Ottaw
ID: 2947012 • Letter: 1
Question
1. (4 points, 0.5 each) You have been observing the local Liberal Party in Ottawa and have compiled some information about a small sample of party regulars. Identify each variable and find the appropriate measures of central tendency for each variable. Calculate the Mean/Median or Mode respectively Explain why you have chosen the given measure(s)* (mean, median or mode) Class Number l Status Number of years in Party 255 1032 1240 2493 High School Maried 2 Masters Single o High School Single F Middle 15 45 IF Middle io M Low ls 1 by | 25 249 lUpper H F Upper 1045 1134 Bachelor Married IF Middle PhD |single 11Explanation / Answer
There are three variables, namely: No of years, no. of children, age.
No of years: In case of numbers of year in party, we shall calculate the mode. Because, while measuring central tendency of this variable, one would be more interested to know, how much years have spent the most in the party by somene.
we observe the mode is 20 years as mode is the highest value, (or the value with highest frequency, in case of frequency distn).
No of children: In this case, a median would be the most appropriate measure of central tendency. because, mode takes value from the known observation, unlike mean. Besides mean can be in decimals, which would be inappropriate in no. of childs.
To calculate the median, we first arrange the data in ascending order as:
0,0,0,1,1,2,2,3
We see there are 8 observations. So median will be any of the 8/2=4th or 8/2 +1 = 5th observation.
So median is 1.
Age: We know age is a continuous variable, So mean would be an appropriate measure.
Mean = (1/8)*[60+45+35+25+29+40+35+18]
=35.9 ~36
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