A company is evaluating the effectiveness of two different training programs to
ID: 2946714 • Letter: A
Question
A company is evaluating the effectiveness of two different training programs to speed up the production process. The employees were placed into three groups and their assembly times were recorded in minutes.
No Training
Training Method 1
Training Method 2
44
48
38
47
52
35
43
43
42
51
39
47
57
49
40
42
41
38
50
37
36
46
40
39
44
45
35
45
41
Test the hypothesis at the .01 level that there is no difference in the population mean times for the three groups.
What is the value of your test statistic from step 3?
Select one:
a. .0023.
b. 13.4333.
c. 2.575.
d. 7.7683.
What is your decision/summarize results (steps 4 and 5)?
Select one:
a. Fail to reject H0. There is a difference in the mean times.
b. Fail to reject H0. There is no difference in the mean times.
c. Reject H0. There is a difference in the mean times.
d. Reject H0. There is no difference in the mean times.
Test the hypothesis at the .01 level that there is no difference in the population mean times for the three groups.
What is your critical value for step 2?
Select one:
a. 4.64.
b. 4.82.
c. 5.53.
d. 7.72.
No Training
Training Method 1
Training Method 2
44
48
38
47
52
35
43
43
42
51
39
47
57
49
40
42
41
38
50
37
36
46
40
39
44
45
35
45
41
Explanation / Answer
Here we need to use one way ANOVA. Hypotheses are:
H0: There is no difference in the population mean times for the three groups.
Ha: There is a difference in the population mean times for the three groups.
Following is the output of one way ANOVA:
The test statistics is:
F = 7.7683
Correct option is d.
The p-value is: 0.0023
Since p-value is less than 0.01 so we reject the null hypothesis.
c. Reject H0. There is a difference in the mean times.
-----------------
The critical value is: 5.53
Correct option is c. 5.53.
Anova: Single Factor SUMMARY Groups Count Sum Average Variance No Training 10 469 46.9 20.98888889 Training Method 1 9 394 43.77777778 25.69444444 Training Method 2 10 391 39.1 13.43333333 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 307.954789 2 153.9773946 7.768252845 0.002264978 5.526334714 Within Groups 515.355556 26 19.82136752 Total 823.310345 28Related Questions
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