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..1 Verizon? 12:24 PM a sru.desire2learn.com A researcher conducts a study to ex

ID: 2946220 • Letter: #

Question

..1 Verizon? 12:24 PM a sru.desire2learn.com A researcher conducts a study to examine the effects of opiate withdrawal treatment on the rate of engaging in risky behaviors. Specifically, 20 individuals suffering from opiate addiction were enrolled in the study. Ten were treated using medication plus behavioral therapy and Ten were given a standard medication only treatment. Patients were followed over a 12 week timeframe, completing surveys about their behavior once per week. The following raw data represents the total number of times each patient engaged in risky behaviors over the course of the study: 16 5 11 4 11 9 16 11 16 16 10 17 10 4. For group A, what are the numerical mean, median, & mode, respectively 5. For Group B, how would the mean, median, and mode, be rank so they were arraigned in ascending order? 6. Based on the relationship between measures of central tendency, how would you describe the distribution for Group B and what's your justification? 7. The Standard Deviation for Group A is 4 and Group B is 5. This added information tells us what about the study data?

Explanation / Answer

4. For group A, the mean of the data is 11.5, and the data in the ascending order is given by

>>> 4 5 9 11 11 11 16 16 16 16

Which means Median = (11+11)/2 = 11

Mode = 16 because frequency of 16 is highest (4)

5. For group B, the mean of the data is 9.3, and the data in the ascending order is given by

>>> 4 4 4 6 6 10 10 15 17 17

Which means Median = (6+10)/2 = 8

Mode = 4 because frequency of 4 is highest (3)

6) Becuase Mode < Median < Mean, we can say that the distribution is positively skewed i.e skewed to the right.

7) This means the dispersion of Group B is higher than Group A.