Martin Ohalete 7/3/18 9:12 PM Homework: Chapter 20 Score: 0 of 1 pt ? 17.1.85-T
ID: 2946043 • Letter: M
Question
Martin Ohalete 7/3/18 9:12 PM Homework: Chapter 20 Score: 0 of 1 pt ? 17.1.85-T 427 of 30 (30 complete) Hw score: 7926%, 2378 of 30 p Question Heip In a study conducted by some Statistics students, 77 people were randomly assigned to listen to rap music, music by Mozart, or no music while attempting to memornze abjects pictured on a page They were then asked to list all the objects they could remember. The summary statistics for each group are shown in the table. Complete parts a and b Rap Mozart No Music Count 34 23 Mean 9.43 8.13 SD 12.87 503 441 277 M correspond to Mozart listeners and group R corespond to rap I isteners. Write the null and altemative hypotheses. Choose the correct answer belaw Test the hypothesis 1--1? (Round to two decimal places as needed ) P-Round to four decimal places as needed) Enter your answer in the answer box and then cack Check Answer remainExplanation / Answer
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: uM - uR = 0
Alternative hypothesis: uM - uR > 0
Note that these hypotheses constitute a one-tailed test.
Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a two-sample t-test of the null hypothesis.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = sqrt[(s12/n1) + (s22/n2)]
SE = 1.26438
DF = 41
t = [ (x1 - x2) - d ] / SE
t = - 3.75
where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is thesize of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between population means, and SE is the standard error.
The observed difference in sample means produced a t statistic of - 3.75.
Therefore, the P-value in this analysis is 0.999.
Interpret results. Since the P-value (0.999) is greater than the significance level (0.05), we cannot reject the null hypothesis.
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