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Solve the system by finding the reduced row-echelon form of the augmented matrix

ID: 2941836 • Letter: S

Question

Solve the system by finding the reduced row-echelon form of the augmented matrix.


A. None
B. Exactly 1
C. Exactly 2
D. Exactly 3
E. Infinitely many
F. None of the above


Solve the system by finding the reduced row-echelon form of the augmented matrix. How many solutions are there to this system? A. None B. Exactly 1 C. Exactly 2 D. Exactly 3 E. Infinitely many F. None of the above If there is one solution, give its coordinates in the answer spaces below. If there are infinitely many solutions, enter z in the answer blank for z, enter a formula for y in terms of z in the answer blank for y and enter a formula for x in terms of z in the answer blank for x. If there are no solutions, leave the answer blanks for x, y and z empty.

Explanation / Answer

1 5 4 1 -1 -8 -13 5 1 4 1 3 Now we will perform Gauss Jordian elimination Add (1 * row1) to row2 1 5 4 1 0 -3 -9 6 1 4 1 3 Add (-1 * row1) to row3 1 5 4 1 0 -3 -9 6 0 -1 -3 2 Divide row2 by -3 1 5 4 1 0 1 3 -2 0 -1 -3 2 Add (1 * row2) to row3 1 5 4 1 0 1 3 -2 0 0 0 0 Add (-5 * row2) to row1 1 0 -11 11 0 1 3 -2 0 0 0 0 Since the last equation becomes all zeros we have infinitely many solutions

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