A textbook cramster answer is as follows in Michael Greenberg\'s Advanced Engine
ID: 2940590 • Letter: A
Question
A textbook cramster answer is as follows in Michael Greenberg's Advanced Engineering Mathematics, 2nd Edition 17.3.16EC part 2: {[e^(3) - e^(-3)](-1)^(n)}/2 = (-1)^(n) sin h 3 = (-1)^(n) i sin 3 I understand that sin h 3 = [e^(3) - e^(-3)]/2 However, doesn't i sin 3 = sin h 3i and not sin h 3? Could the (-1)^(n) somehow provide the missing i? Or could the cramster solution be wrong? A textbook cramster answer is as follows in Michael Greenberg's Advanced Engineering Mathematics, 2nd Edition 17.3.16EC part 2: {[e^(3) - e^(-3)](-1)^(n)}/2 = (-1)^(n) sin h 3 = (-1)^(n) i sin 3 I understand that sin h 3 = [e^(3) - e^(-3)]/2 However, doesn't i sin 3 = sin h 3i and not sin h 3? Could the (-1)^(n) somehow provide the missing i? Or could the cramster solution be wrong?Explanation / Answer
{[e^(3) - e^(-3)](-1)^(n)}/2 = (-1)^(n) sin h 3 is right. sinh(x) = -i sin(ix) so sin h 3 = i sin 3 is wrong, sinh(3) = -i sin(3i)
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