W = span{ [2,5,-1],[5,2,-1],[7,7,-2],[-1,8,-1],[-12,-9,6] }. 4.1 (1 mark) First
ID: 2938693 • Letter: W
Question
W = span{ [2,5,-1],[5,2,-1],[7,7,-2],[-1,8,-1],[-12,-9,6] }.4.1(1 mark) First enter your basis for W as a set ofR3 row vectors where each row vector isentered as a list.
A basis for W =
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4.2(1 mark)
dim(W) =
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4.1(1 mark) First enter your basis for W as a set ofR3 row vectors where each row vector isentered as a list.
A basis for W =
You have not attempted this yet
4.1(1 mark) First enter your basis for W as a set ofR3 row vectors where each row vector isentered as a list.
A basis for W =
4.2(1 mark)
dim(W) =
You have not attempted this yet
4.2(1 mark)
dim(W) =
W = span{ [2,5,-1],[5,2,-1],[7,7,-2],[-1,8,-1],[-12,-9,6] }.
Explanation / Answer
SEE THE FOLLOWING ANALOGOUSEXAMPLE AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK
Response Details: QuestionDetails: 4.1 First enter your basis for W as a set ofR3 row vectors where each row vector isentered as a list.
A basis for W = (-3,4,3),(-1,2,-3),(7,-10,13)
4.1 First enter your basis for W as a set ofR3 row vectors where each row vector isentered as a list.
A basis for W = (-3,4,3),(-1,2,-3),(7,-10,13)
4.2
dim(W) = 3....THREE 4.2
dim(W) = 3....THREE W = span{ [-3,4,-3],[-1,2,-3],[-4,6,-6],[5,-8,9],[7,-10,13] }.
W=
V1 V2 V3 V4 V5
-3 -1 -4 5 7
4 2 6 -8 -10
-3 -3 -6 9 13
NR1=-R1/3…..NR2=R2+4R1/3….NR3=R3-R1
1 0.333333333 1.333333333 -1.666666667 -2.333333333
0 0.666666667 0.666666667 -1.333333333 -0.666666667
0 -2 -2 4 6
NR1=R1-R2/2….NR2=1.5R2….NR3=R3+3R2
1 0 1 -1 -2
0 1 1 -2 -1
0 0 0 0 4
THERE IS NO ALL ZEROS ROW
SO WE NEED 3 INDEPENDENT VECTORS TO FORM BASIS
SO WE CAN TAKE V1,V2,V5 AS THE BASIS
DIMENSION IS 3
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