suppose we obtain a 90% confidence interval for the average # of raisins in a 1/

Question

suppose we obtain a 90% confidence interval for the average # of raisins in a 1/2 oz box is [30.5,31.5] using a sample of 64 raisins. what is wrong with each of the following statements ((a) and (b)) with regading to the explanation of this 90 % confidence interval:

(A) "we are 90% sure that the sam;le average # of raisins of the 64 boxes is between 30.5 to 31.5"

(b) "we are 90% sure of the # of the raisins in each individual box is between 30.5 ro 31.5"

(C) give a correct interpretation of the above 90% confidence interval:

Explanation / Answer

It will be correct to say that there is 90% chance that the cinfidence interval contains the true mean of population of 64 boxes.

C) At 90% cinfidence interval the critical value Z* = 1.96

Confidence interval = mean +/- Z* * SD/sqrt(n )

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