Score: 0.13 of 1 pt 23of23(23 complete) 11.7.73 This exercise is on probables an

Question

Score: 0.13 of 1 pt 23of23(23 complete) 11.7.73 This exercise is on probables and coincidence of shared bitdays Complete parts (a) through (e) below 364 365 365 Explain why his is so (Ignore leap years and assume 365 days in a year) The fist person can have any bithday, so they can have a birthday on 365 of the 35 days In order for the second p The irst person can have any birthday, so person to not have the same birthday they must have one of the 364 remaining birthdays (Type whole numbers) b It four people are selected at random, find the probabilty that they alt have diffecrent birthdays The probability that they all have different birthdays is (Round to three decimal places as needed )

Explanation / Answer

Solution:-

the probability that they all have different birthdays is 0.984

=> Solution:-365/365 * 364/365 * 363/365* 362/365 =0.9836

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