Ex: In a crash test of 15 Honda Odyssey minivans, collision repair costs are fou
ID: 2935946 • Letter: E
Question
Ex: In a crash test of 15 Honda Odyssey minivans, collision repair costs are found to have an approximately normal distribution with a sample mean of $1,786. Below is a 99% confidence interval for the mean repair cost in all such vehicle collisions.
The confidence interval is used to test the null hypothesis that the true mean repair cost is $2600. If, in fact, the true mean repair cost is $2600, what would your statistical decision be? Note: We haven't covered confidence interval for means, but the same duality principles and error definition exist.
Reject the null, the p-value must be less than a significance level of 0.01.
Fail to reject the null, the p-value must be less than a significance level of 0.01.
Fail to reject the null, the p-value must be more than a significance level of 0.01.
Reject the null, the p-value must be more than a significance level of 0.01.
2. In the previous question, if the decision made was an error, what type of error was it? Type I , Type II, Type III, or Power
Variable N Sample Mean 99% Confidence Interval Repair Cost 15 $1786 ($1066, $2506)Explanation / Answer
we are given that the 99% confidence interval is
($1066, $2506)
this means that we are 99% sure that the true mean would lie in the range 1066 and 2506 , there is only 1% chance that the true mean would lie outside this range
null hypothesis that the true mean repair cost is $2600
alternate hypothes is the true mean repair cost is different from $2600
hence based on the confidence interval we
Reject the null, the p-value must be less than a significance level of 0.01.
Also , we know that
type 1 error is : reject null hypothesis when you should not
type 2 error is : accept null hypothesis when you should not
here we are reject the null hypothesis , and if it were wrong , this is a type 1 error .
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