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Given a standardized normal distribution (with a mean of 0 and a standard deviat

ID: 2935293 • Letter: G

Question

Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d) E Click here to view page 1 of the armulative standardized normal distribution table Click here to view page 2 ofthe cumulative standardized normal distribution ta ble. a. What is the probability that Z is less than 1.017 The probability that Z is less than 1.01 is Round to four decimal places as needed.) b. What is the probability that Z is greater than-0.23 The probability that Z is greater than-023 is Round to four decimal places as needed.) c. What is the probability that Z is less than -0.23 or greater than the mean? The probability that Z is loss than -023 or greater than the mean is Round to four decimal places as needed.) d. What is the probability that Z is less than-023 or greater than 101? The probability that Z is less than-0.23 or groater than 1.01 is (Round to four decimal places as needed.) Enter your answer in each of the answer boxes. Save for Later d' data-10-29-2017-11 sisx . MacBook Air 808 esc F1 4 2

Explanation / Answer

a.

P(Z<1.01) = 0.8438 ..............Using Excel function =NORMSDIST(1.01) we will ge 0.8438

b.

P(Z>-0.23)=1-P(Z<-0.23)=1-0.4090=0.5909

c.

P(-0.23<Z<0)=P(Z<0)-P(Z<-0.23)=0.5-0.4090=0.09095

d.

P(-0.23<Z<1.01)=P(Z<1.01)-P(Z<-0.23)=0.8438-0.4090=0.4347

Hope this will be helpful thanksa nd God Bless you :-)

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