A person is to walk into a casino and play a certain game. The chance the person
ID: 2935185 • Letter: A
Question
A person is to walk into a casino and play a certain game. The chance the person will win the game is 0.3. Once they play the first game, win or lose, they are to play the game 3 more times for a total of 4 games.
A random variable XX is to count how many of the 4 games the gambler wins.
(a) Finish the probability distribution of XX below. Use four decimals in each of your entries.
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(b) From the distribution you found in part (a), what can you say about the distribution of XX?
The distribution of XX is ? symmetrical skewed to the right skewed to the left , with an mean of
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games won and a standard deviation of
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games won.
XX 0 1 2 3 4 P(X=x)P(X=x)equation editor
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Equation EditorExplanation / Answer
for binomial distribution n=4; p=0.3
hence probability of winning x games =P(X=x)=4Cx *(0.3)x*(1-0.3)4-x
from above below is probability distribution:
b)
distribution of X is skewed to the right with an mean of =np =4*0.3 =1.2 games won and a standard deviation of
=(np(1-p))1/2=0.9165 games won.
x 0 1 2 3 4 P(x) 0.2401 0.4116 0.2646 0.0756 0.0081Related Questions
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