Anova calculation formulas are presented below. The printout below is for an unb

Question

Anova calculation formulas are presented below. The printout below is for an unbalanced single-factor ANOVA model for the Battery Life Test (in hours) for alkaline batteries supplied by three different companies. Complete the ANOVA table below and calculate the F test statistic for Ho: A = B = C. You should attempt to achieve four decimal places of accuracy. Question 7 options: Spell check Save Question 8 (4 points) Question 8 Unsaved Refer to the information presented in the previous question. Select an appropriate significance level and state your decision regarding the hypotheses tested. Question 8 options: Spell check Save Question 9 (3 points) Question 9 Unsaved Refer to the information presented in question 6 above. From this analysis what conclusions can you draw about the test life of the batteries from the three suppliers?

SUMMARY Groups Count Sum Average Variance 14 119.000 8.50 A - Energizer B- Eveready C-Duracell 0.6850 0.7500 18 8.15 146.700 117.260 13 9.02 0.8050 ANOVA Source of variation df MS Between Groups within Groups Total 37.0305

Explanation / Answer

Ho: There is no difference between means of three grouops

H1: There is a difference between means of three groups

alpha:%

Conclusion:

P =0.02959 <0.05, we reject the H0. Hence claim is significant.

ANOVA ONE Way Sorce df ss ms F cal F critical P value Regression 2 5.7155 2.85775 3.832574 3.219942 0.02959 Residual 42 31.3172 0.745648 Total 44 37.0326

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