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All green wants to open a franchise in a new neighborhood and wants to estimate

ID: 2932134 • Letter: A

Question

All green wants to open a franchise in a new neighborhood and wants to estimate its potential sales. The store will have 3000 square feet; will serve 10,000 households; will invest $8,000 in advertising; will have 4 competitors in the area; and will carry $45,500 in inventories

For the following problem provide:

–Correlation analysis

–Regression analysis

Explain your decision making and interpret your results.

Annual sales [$000]

Area

Inventory [$000]

Advertising [$000]

Households[000]

Competitors

[1000 sft]

231

3

29.4

8.2

8.2

11

156

2.2

23.2

6.9

4.1

12

10

0.5

14.9

3

4.3

15

519

5.5

60

12

16.1

1

437

4.4

56.7

10.6

14.1

5

487

4.8

57.1

11.8

12.7

4

299

3.1

51.2

8.1

10.1

10

195

2.5

34.7

7.7

8.4

12

20

1.2

21.2

3.3

2.1

15

68

0.6

10.2

4.9

4.7

8

570

5.4

78.8

17.4

12.3

1

428

4.2

57.7

10.5

14

7

464

4.7

53.5

11.3

15

3

15

0.6

16.3

2.5

2.5

14

65

1.2

16.8

4.7

3.3

11

98

1.6

15.1

4.6

2.7

10

398

4.3

34.2

5.5

16

4

161

2.6

19.6

7.2

6.3

13

397

3.8

45.3

10.4

13.9

7

497

5.3

51.8

11.5

16.3

1

528

5.6

61.5

12.3

16

0

99

0.8

27.8

2.8

6.5

14

0.5

1.1

14.2

3.1

1.6

12

347

3.6

46.1

9.6

11.3

6

341

3.5

38.2

9.8

11.5

5

507

5.1

59

12

15.7

0

400

8.6

51.7

7

12

8

Annual sales [$000]

Area

Inventory [$000]

Advertising [$000]

Households[000]

Competitors

[1000 sft]

231

3

29.4

8.2

8.2

11

156

2.2

23.2

6.9

4.1

12

10

0.5

14.9

3

4.3

15

519

5.5

60

12

16.1

1

437

4.4

56.7

10.6

14.1

5

487

4.8

57.1

11.8

12.7

4

299

3.1

51.2

8.1

10.1

10

195

2.5

34.7

7.7

8.4

12

20

1.2

21.2

3.3

2.1

15

68

0.6

10.2

4.9

4.7

8

570

5.4

78.8

17.4

12.3

1

428

4.2

57.7

10.5

14

7

464

4.7

53.5

11.3

15

3

15

0.6

16.3

2.5

2.5

14

65

1.2

16.8

4.7

3.3

11

98

1.6

15.1

4.6

2.7

10

398

4.3

34.2

5.5

16

4

161

2.6

19.6

7.2

6.3

13

397

3.8

45.3

10.4

13.9

7

497

5.3

51.8

11.5

16.3

1

528

5.6

61.5

12.3

16

0

99

0.8

27.8

2.8

6.5

14

0.5

1.1

14.2

3.1

1.6

12

347

3.6

46.1

9.6

11.3

6

341

3.5

38.2

9.8

11.5

5

507

5.1

59

12

15.7

0

400

8.6

51.7

7

12

8

Explanation / Answer

Solution:

For the given data, first of all we have to find out the correlation coefficients exists between the different pairs of the variables. The correlation coefficients between the different variables are summarized as below:

Annual sales [$000]

Area (1000 sft)

Inventory [$000]

Advertising [$000]

Households[000]

Competitors

Annual sales [$000]

1

Area (1000 sft)

0.894092082

1

Inventory [$000]

0.945503625

0.843615783

1

Advertising [$000]

0.914024068

0.748587237

0.906230642

1

Households[000]

0.953683059

0.838022883

0.863916915

0.795434449

1

Competitors

-0.912236392

-0.765737788

-0.807380423

-0.841279944

-0.869589611

1

It is observed that there are strong positive linear relationships or associations exist between the annual sales and independent variables such as area, inventory, advertising, and households. Also, it is observed that there is a strong negative linear relationship exists between the annual sales and competitors. If the number of competitors are increases, then annual sale is decreases.

Now, we have to see regression analysis for the estimation of the annual sales. For this regression model, we assume dependent variable or response variable as the annual sale and independent variables or explanatory variables as area, inventory, advertising, households, and competitors. The regression analysis is given as below:

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.996583913

R Square

0.993179497

Adjusted R Square

0.991555567

Standard Error

17.64924228

Observations

27

ANOVA

df

SS

MS

F

Significance F

Regression

5

952538.941

190507.7882

611.5903232

0.00

Residual

21

6541.410811

311.4957529

Total

26

959080.3519

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

-18.85940731

30.15022856

-0.625514572

0.538372488

-81.5602398

43.84142519

Area (1000 sft)

16.20157256

3.544437472

4.570985577

0.000165985

8.830511351

23.57263377

Inventory [$000]

1.746351825

0.576060683

3.031541426

0.006346786

0.548368057

2.944335593

Advertising [$000]

11.52626787

2.532103272

4.552052832

0.000173652

6.260470868

16.79206487

Households[000]

13.58031268

1.770456651

7.670514089

1.60544E-07

9.898446535

17.26217883

Competitors

-5.310971819

1.705426574

-3.114160352

0.005248871

-8.85760052

-1.764343118

The multiple correlation coefficient is given as 0.9966 which indicate strong relationship between the dependent variable and independent variables. The value of the R-square or coefficient of determination is given as 0.9932, which means about 99.32% of the variation in the dependent variable is explained by the independent variables such as area, inventory, advertising, households, and competitors.

The p-value for this regression equation is given as 0.00 which means the there is a statistically significant linear relationship exists between the dependent variable and independent variables.

Regression equation is given as below:

Annual sales = -18.85940731 + 16.20157256* Area (1000 sft) + 1.746351825*Inventory [$000] +

11.52626787*Advertising [$000] + 13.58031268* Households[000] - 5.310971819* Competitors

By using this regression equation we can easily estimate the value for annual sales.

Annual sales [$000]

Area (1000 sft)

Inventory [$000]

Advertising [$000]

Households[000]

Competitors

Annual sales [$000]

1

Area (1000 sft)

0.894092082

1

Inventory [$000]

0.945503625

0.843615783

1

Advertising [$000]

0.914024068

0.748587237

0.906230642

1

Households[000]

0.953683059

0.838022883

0.863916915

0.795434449

1

Competitors

-0.912236392

-0.765737788

-0.807380423

-0.841279944

-0.869589611

1

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