defects 2 2 1 3 3 4 2 2 2 2 1 2 1 3 1 2 2 5 6 1 0 1 1 1 5 1 4 2 4 0 2 1 2 4 0 1

Question

defects 2 2 1 3 3 4 2 2 2 2 1 2 1 3 1 2 2 5 6 1 0 1 1 1 5 1 4 2 4 0 2 1 2 4 0 1 3 2 3 1 1 5 3 2 3 4 6 1 4 6 2. 3/4 points |Previous Answers My No A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random sample of 36 bins, the sample mean amount was 49.32 pounds and the sample standard deviation was 3.7 pounds. Conduct the appropriate hypothesis test using a 0.05 level of significance b) What is the test statistic? Give your answer to four decimal places. 1.103 c) What is the P-value for the test? Give your answer to four decimal places. 0.2776

Explanation / Answer

Question 2

Sample size n = 36

sample mean x = 49.32 pounds

sample stanard deviation s = 3.7 pounds

Test statistic

t = (49.32 - 50)/ (3.7 /sqrt(36) = -1.1027

(b) P - value = 2 * Pr(t < -1.1027 ; dF = 35) = 0.2777

Question 3

H0 : Mean number of defects = 1.78

Ha : Mean number of defects > 1.78

Sample mean number of defects x = 120/50 = 2.4

standard deviation of mean number of defects (s) = 1.5908

Test Statistic

t = (2.4 - 1.78)/ (1.5908/ sqrt(50)) = 0.62/ 0.2250 = 2.7559

P- value for the test = Pr(t > 2.7556, 0.49) = 0.0041

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