. Assume we observe the following data set for percent loss in efficiency with r

Question

. Assume we observe the following data set for percent loss in efficiency with respect to the maximum yield in 10 identical trials in a chemical reactor. (0.39,0.13,0.70, 0.10, 0.86,0.10,0.14,0.05,0.01,0.60) For example in the first reaction the yield was 0.39 below the maximum yield that can be obtained. We do not know the probability mechanism (distribu- tion) that generates these loss in efficiencies for this reaction. Give a formula for the estimator of the standard error of the sampling distribution of the sample mean,

Explanation / Answer

Here the standard error of the sampling distribution of the sample mean = sqrt[2/ N ] or sqrt [s2/N]

Here sample mean of loss in effciency w.rt. maximum yield = 0.308

Sample standard deviation of loss in efficiency w.r.t. maximum yield s = 0.3077

standard error of the sampling distribution of the sample mean = sqrt [s2/N]

= 0.3077 / sqrt(10) = 0.0973

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