eviation, s, of sample data summarized in the frequency distribution table below
ID: 2929516 • Letter: E
Question
eviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midpoint, f represents the class frequency, obtained from the original list of data values, 11.1 and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation n(n -1) 27-33 41-47 48-54 55-61 34 34-40 62-68 39 Interval 20-26 Frequency 10 Standard deviation(Round to one decimal place as needed.) Consider a difference of 20% between two values of a standard de ation to be significant. How does this computed value compare with the given standard deviation, A The computed value is signicantly less than the given value. O B. The computed value is not significantly different from the given value. O C. The computed value is significantly greater than the given value.Explanation / Answer
from above formula :
std deviation =((93*318403-53732)/(93*92))1/2 =9.3
as 11.1 is not more then 20% abvove hence option B is corect.
Bin mid point(x) frequency fx fx2 20-26 23 2 46 1058 27-33 30 1 30 900 34-40 37 4 148 5476 41-47 44 3 132 5808 48-54 51 10 510 26010 55-61 58 34 1972 114376 62-68 65 39 2535 164775 93 5373 318403Related Questions
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