(1 point) A study of the career paths of hotel general managers sent questionnai
ID: 2929453 • Letter: #
Question
(1 point) A study of the career paths of hotel general managers sent questionnaires to an SRS of 270 hotels belonging to major U.S. hotel chains. There were 148 responses. The average time these 148 general managers had spent with their current company was 8.34 years. (Take it as known that the standard deviation of time with the company for all general managers is 2.9 years.) (a) Find the margin of error for an 80% confidence interval to estimate the mean time a general manager had spent with their current company: years (b) Find the margin of error for a 99% confidence interval to estimate the mean time a general manager had spent with their current company: *years the margin of error (width) of the (c) In general, increasing the confidence level confidence interval. (Enter: "DECREASES', "DOES NOT CHANGE" or "INCREASES", without the quotes.)Explanation / Answer
A) Z for 80% confidence interval = Z0.9 = 1.28
Margin of error = Z * sd/sqrt (n) = 1.28 * 2.9 / sqrt(148) = 0.305
B) Z score for 99%confidence interval = Z0.995 = 2.575
Margin of error = Z * sd/sqrt(n) = 2.575 * 2.9/sqrt (148) = 0.614
C) increases
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.