According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M

Question

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123]

Compute the probability that a randomly selected peanut M&M is not orange.



Compute the probability that a randomly selected peanut M&M is yellow or green.



Compute the probability that three randomly selected peanut M&M’s are all blue.



If you randomly select four peanut M&M’s, compute that probability that none of them are orange.



If you randomly select four peanut M&M’s, compute that probability that at least one of them is orange.

Explanation / Answer

a) probability that a randomly selected peanut M&M is not orange = 1 - P(orange)

P = 1 - 0.23 = 0.77

b) probability that a randomly selected peanut M&M is yellow or green = 0.15 + 0.15 = 0.3

c) probability that three randomly selected peanut M&M’s are all blue = 0.23^3 = 0.012

d) probability that none of them are orange = (1 - 0.23)^4 = 0.352

e) probability that at least one of them is orange = 1 - 0.352 = 0.648

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