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File Home Insert Draw Page Laout Fomalas Dats ReviewVTell me wihet you want to d

ID: 2928325 • Letter: F

Question

File Home Insert Draw Page Laout Fomalas Dats ReviewVTell me wihet you want to do General Copy . Format PainterIu aste Forr Cipboard Fent 51 f. 5 4. Exercise 4 A pear sorting process yiekds pears with mean mass of 200 g and standard 7 deviation of 18 g Sets of 5 pears are put in each bag and sold as 1 kg mean 200 18 standard deviation a. What proportion of bags are expected to have less than 950 g?10] mean bag weight variance of bag weight P(Y950) b what proportion of bags are expected to have more than 1075 g? variance of bag weight = P(Y 1075) Exercises

Explanation / Answer

a) Mean bag weight= "=5*E8"
Variance of bag weight= "=5*(E9^2)"

P(Y < 950) = "=NORM.DIST(950, B13, sqrt(B14), TRUE)"

Type in the formulas given between double quotes.

NORM.DIST is used to find probability of normal distributions.

This question is related to the addition of random variables. Independent random variables. This means that thesum of two independent normally distributed random variables is normal, with its mean being the sum of the two means, and its variance being the sum of the two variances

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