18. Below is a survey of 615 students regarding satisfact tion with the choice t

Question

18. Below is a survey of 615 students regarding satisfact tion with the choice their majors. Maths Biology Physics English Total Very satisfied 27 Satisfied 47 39 13 52 95 160 12 30 82 124 61 182 Not Satisfied 58 Total 334 615 146 185 Assume that the sample represents the entire population of students. Find the probability that a student selected at random is a. At least satisfied with her/his major. [Ans: 0.4569] 99 +182 P(At least Satisfied)615 --= 0.4569 b. Satisfied, given that she/he is a Mathematics mojor. LAns: 0.4178] p(Satisfied|Math)-P(Satisfied nMath) = 61/ c. Not satisfied. given that she/he is a Biology mojor. (Ans: 0.53511 /615. = 0.4178 146 615 P(Not Satisfied n Bio) 99615 P(Not Eng)-1-P(Eng)-1-615-0.7984 P(Satisfied Math)P(Math) P(Not Satisfied|Bio) d. Not an English major. [Ans: 0.7984 e. Either a biology major or a math major. [Ans: 0.538] P(Bio) 185/ 124 f. Is an English mojor given that they are very satisfied. [Ans: 0.121] g. Is a Math major or a student who is satisfied? [Ans: 0.434] h. Is a Physics major and not satisfied? [Ans: 0.154] i. Is a very satisfied student given that their major is biology. [Ans: 0.254]

Explanation / Answer

Answer to the questions are:

e.P( either bio or math major) = (185+146)/615 = .538

f. P( given very satisfied , he' english) = 12/99 = .121

g. P( given satisfied or he' math major) = (146+182-61)/615 = .434

h. P( physics major and not satisfied) = 95/615 = .154

i. P(is very satisfied given bio major) = 47/185 = .254

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