According to a random sample taken at 12 A.M., body temperatures of healthy adul

Question

According to a random sample taken at 12 A.M., body temperatures of healthy adults have abell-shaped distribution with a mean of

98.1798.17degrees°F

and a standard deviation of

0.610.61degrees°F.

UsingChebyshev's theorem, what do we know about the percentage of healthy adults with body temperatures that are within

33

standard deviations of the mean? What are the minimum and maximum possible body temperatures that are within

33

standard deviations of the mean?

At least

nothing%

of healthy adults have body temperatures within

33

standard deviations of

98.1798.17degrees°F.

(Round to the nearest percent as needed.)

The minimum possible body temperature that is within

33

standard deviations of the mean is

nothingdegrees°F.

(Round to two decimal places as needed.)

The maximum possible body temperature that is within

33

standard deviations of the mean is

nothingdegrees°F.

(Round to two decimal places as needed.)

Explanation / Answer

a) percentage of healthy adults with body temperatures that are within 3 standard deviations of the mean = 1 - (1/3)2 = 88.89%

b) minimum possible body temperature = mean - 3 * sd = 98.17 - 3 * 0.61 = 96.34

maximum possible body temperature = mean + 3 * sd = 98.17 + 3 * 0.61 = 100

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