1) Iron-deficiency anemia is an important nutritional health problem in the Unit
ID: 2926326 • Letter: 1
Question
1) Iron-deficiency anemia is an important nutritional health problem in the United States. A dietary assessment was performed on 86 boys 9 to 11 years of age whose family incomes were below the poverty level. The mean daily iron intake among these boys was found to be 13.31 mg with standard deviation 4.46 mg Previous studies indicate the mean daily iron intake in the general population of 9- to 11-year- old boys from all income strata is 14.58 mg and -5.43 me.The researchers want to test whether the mean iron intake among the low-income group is different from that of the general population at the OS (5 %) level of significance A) This study: [circle correct answer(s)]: [3] (a) Is designed to test hypothesized equivalence of a sample mean and a reference value (b) Is designed to test hypothesized equivalence of population mean and a reference value (c) Could use a Z-test for one population mean to test a hypothesis of equivalence to a reference value B) Based on the sample, what is the value of the point estimate of for the population of all OLLncome boys, ages 9 to 11 years? C) In a hypothesis test, the researchers assume that the null hypothesis is (true/false) and look for (confirm /reject) this assumption D) A Type leror would occur if, in fact, mean daily iron intake is 14.58 mg in the low income population, but evidence to the results of the hypothesis test lead the researchers to The long-term probability of this occurring that is given for this example is . One reason why Type 1 (and Type II) errors occur is E) Assume the required conditions for the test are met and calculate the value of the test statisticExplanation / Answer
solutionA:
we are checking
Ho: mu=14.58
H1:mu not =14.58
could use z test as population std deviation is known
OPTIONC
solutionB:
Point estimate=sample mean=13.31
Solutionc:
assume null hypothesis is true and look for evidence to reject the null hypothesis
TRUE and REJECT
PVALUE and LEVEL OF SIGNIFICANCE
SolutionE:
z=sample mean-population mean/sd/swrt(n)
=13.31-14.58/5.43/sqrt(86)
=-2.17
z stat=-2.17
SolutionD:
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