Time, Years Number at Risk Nt Number of Deaths Dt Number Censored Ct Survival Pr
ID: 2925087 • Letter: T
Question
Time, Years
Number at Risk
Nt
Number of Deaths
Dt
Number Censored
Ct
Survival Probability
St+1 = St*((Nt-Dt)/Nt)
0
25
1
1.2
25
1
0.960
2.5
24
1
0.920
3.4
23
1
0.920
4.1
22
1
0.920
4.2
21
1
0.920
4.3
20
1
0.874
5.6
19
1
0.828
5.7
18
1
0.828
5.9
17
1
0.828
6.3
16
1
0.828
6.4
15
1
0.828
6.5
14
1
0.828
6.7
13
1
0.764
7.3
12
1
1
0.700
8.1
10
1
0.630
8.2
9
1
0.630
8.6
8
1
0.630
8.9
7
1
0.630
9.4
6
1
0.630
9.5
5
1
0.630
10.0
4
4
0.630
Referring to the graph above:
What is the probability of surviving 6.5 years?
A. 0.35
B. 0.15
C. 0.99
D. None of the above
Patients have an 85% chance of surviving how many years?
A. 6.0
B. 4.25
C. 3.2
D. 5.5
Time, Years
Number at Risk
Nt
Number of Deaths
Dt
Number Censored
Ct
Survival Probability
St+1 = St*((Nt-Dt)/Nt)
0
25
1
1.2
25
1
0.960
2.5
24
1
0.920
3.4
23
1
0.920
4.1
22
1
0.920
4.2
21
1
0.920
4.3
20
1
0.874
5.6
19
1
0.828
5.7
18
1
0.828
5.9
17
1
0.828
6.3
16
1
0.828
6.4
15
1
0.828
6.5
14
1
0.828
6.7
13
1
0.764
7.3
12
1
1
0.700
8.1
10
1
0.630
8.2
9
1
0.630
8.6
8
1
0.630
8.9
7
1
0.630
9.4
6
1
0.630
9.5
5
1
0.630
10.0
4
4
0.630
0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 2 3 4 10 Time, YearsExplanation / Answer
1) P(6.5) = 828
D. None of the above
2) P(X) = 0.85 falls between 4.3 and 5.6
Therefore only option is D. 5.6
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