The mean number of flaws per square meter in a length of fabric is 4. Assume tha

Question

The mean number of flaws per square meter in a length of fabric is 4. Assume that the flaws occur randomly and independently so that the Poisson distribution applies. Answer the following questions to 3 places after the decimal point. a) What is the probability of 2 flaws in a square meter? Submit Answer Tries 0/5 b) What is the probability of at least 1 flaw in a square meter? Submit Answer Tries 0/5 c) What is the probability of at most 1 flaw in 2 square meters of fabric? Submit Answer Tries 0/5

Explanation / Answer

= 4

P(X = x) = e- * x / x!

a) P(X = 2) = e-4 * 42 / 2! = 0.147

b) P(X > 1) = 1 - P(X = 0)

                   = 1 - e-4 * 40 / 0!

                   = 1 - 0.018

                   = 0.982

c) = 4*2 = 8

P(X < 1) = P(X = 0) + P(X = 1)

              = e-8 * 80 / 0! + e-8 * 81 / 1!

              = 0.003

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