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Based on the IQ scores for 12 of her children, Michelle Duggar performs a hypoth

ID: 2924880 • Letter: B

Question

Based on the IQ scores for 12 of her children, Michelle Duggar performs a hypothesis test to see if her children are significantly (a 01) more intelligent than the average person in the population at large ( IQ score-100). What is test statistic, decision, and appropriate conclusion for this test (see raw data below)? 125 3 115 7 102 2 09.234 Reject the null hypothesis. Results suggest the Duggar children are significantly more intelligent than the average person. Ot-9.234 Fail to reject the null hypothesis. Results suggest the Duggar children are not significantly more intelligent than the average person O t = 9.234 Reject the null hypothesis. Results suggest the Duggar children are not significantly more intelligent than the average person. O t-2.015 Reject the null hypothesis. Results suggest the Duggar children are significantly more intelligent than the average person O t = 2015 Fail to reject the null hypothesis. Results suggest the Duggar children are not significantly more intelligent than the average person. t-2.015 Reject the null hypothesis. Results suggest the Duggar children are not significantly more intelligent than the average person. t = 6.982 Fail to reject the null hypothesis. Results suggest the Duggar children are not significantly more intelligent than the average person. t = 6.982 Reject the null hypothesis. Results suggest the Duggar children are significantly more intelligent than the average person. t-6.982 Reject the null hypothesis. Results suggest the Duggar children are not significantly more intelligent than the average person. O

Explanation / Answer

The statistical software output for this problem is:

One sample T hypothesis test:
: Mean of variable
H0 : = 100
HA : > 100

Hypothesis test results:

Hence,

The option marked is not correct. The one below it (Second last option) is correct.

Variable Sample Mean Std. Err. DF T-Stat P-value Data 115.33333 2.1961859 11 6.9818013 <0.0001
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