will you answer these please!!! [Use the following information to answer the nex

Question

will you answer these please!!!

[Use the following information to answer the next 2 questions./ The histogram and frequency table below display the number of servings of vegetables eaten by 250 college students on a randomly selected day. Frequencies Level Count Prob 22 0.08800 82 0.32800 38 0.15200 43 0.17200 33 0.13200 26 0.10400 0.02000 1 0.00400 Total 250 1.00000 0.353 0.30 0254 0.20 5 0.15 0.10 a 6 82- 26 5 1 0.05 7 0 1 2.3 45 6 7 13. The FDA recommends at least three servings a day of vegetables; what proportion of students in this sample meet the FDA's recommendation? a) 0.172 b) 0.432 c) 0.568 d) 0.584 e) 0.828

Explanation / Answer

13. P(X>=3) = 1-P(X<3) = 1-(.088+.328+.152) = .432
b is right

14. Since it is skewed distribution measures of center and spread should not be Mean.
So, b, e are ruled out.

The standard deviation is not a good measure of spread in highly-skewed distributions and should be supplemented in those cases by the semi-interquartile range. So, a is ruled out. d is right

Answers to the individual questions below:

15.
Mean = 71
Stdev = 3
P(risk of hitting door frame) = P(X>80) = P(Z> 80-71/3) = P(Z>3) = .00135
So, answer is a) 0.13%

16. The population of interest is restricted to patient with this particular form of anemia.
So, e. is right.

17.Thats would be 2 deviations or a Z of -1.96 and 1.96 for 95% chance according to Empirical Rule

So, 95% chance that the it will be between = p+/-Z*sqrt(p*p'/n) = 0.30 +/- 1.96*sqrt(.3*.7/100) = .21 to .39

d. is right

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.