1: What is the force of gravity between two objects, each with mass 1, that are

Question

1: What is the force of gravity between two objects, each with mass 1, that are 2 apart?

2: What is the force of gravity between two objects, each with mass 2 that are at a distance of 2 from each other? How does that compare to the force when they’re only 1 from each other?

3: IN WORDS, how does the force of gravity change when the distance between the objects changes?

4: IN WORDS, how does the force of Earth’s gravity change if you are at the peak of Mount Everest (8,848 meters above sea level), compared to being in Oahu, Hawaii (at sea level)? Where do you weigh more? You should be able to answer this without calculations.

Explanation / Answer

1)

force of gravity F = GM1M2/R2

G = GRAVITATIONAL CONSTANT = 6.674×10-11 m3kg-1s-2

M1, M2 masses of the planets

R= distance between the planets

M1,M2= 1

R = 2

F = G x1 x1/ 22= G/4 = 1.668×10-11 N

2).

M1,M2 = 2

R= 2

F1 = Gx2 x2 / 22 = G = 6.674×10-11 N

F2= Gx2 x2 / 12 = 4G = 26.696×10-11 N

F2>>F1

3)

F = GM1M2/R2

F is inversely variable with the square of the Distance(R)

when radius increases the force decreses at square rate of R

4)

F = GM1M2/R2

gravitational aceleration A = GM/R2  

G = 6.674×10-11 m3kg-1s-2

M = mass of earth =  6 x 1024kg

R = R = radius of earth 6400 km = 6400000m

at the mount everest height = 8848 m

R1 = 6408848 m

A1 =  6.674×10-11 m3kg-1s-2 x 6 x 1024kg / ( 6408848 m)2 = 9.75 m/s2

at the Oahu, Hawaii (at sea level)

R2 = 6400000 m

A2 = 6.674×10-11 m3kg-1s-2 x 6 x 1024kg / ( 6400000 m)2 = 9.78 m/s2

the A2 > A1

so weight at Oahu, Hawaii (at sea level) is greater than the at the peak of Mount Everest.

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