For this assignment, you submit answers by question parts.The number of submissi

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For this assignment, you submit answers by question parts.The number of submissions remaining for each question part only changes if you submit or change the answer Assignment Seering Your last submission is used for your score -zinfandel, 8 of merlot, and 11 of cabernet (he only driniks red wine), all from difflerent A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of wineries are there to do this (a) If he wants to serve 3 bottles of zinfandel and serving order is important, how many ways 783 of wine are to be randomly selected from the 28 for serving, how many ways are ways (c) If 6 bottles are randomly selected, how many ways are there to obtain two bottles of each (d) It 6 bottles are rando (e) It 6 bottles are randomly selected, what is the probability that all of them are the same vanety? (Round your answer to three decimal places) varlety? miy selected, what is the probability that this results in two bottles of each variety being chosen? (Round your answer to three decimal Need Help? Sutbmit Answer Save Progress Practice Another Vension 6

Explanation / Answer

a)

Since serving order is importent we use permutation here.

3 bottles are served from 9 bottles by 9P3 ways .

That is 9*8*7 = 504 ways.

b)

6 bottles are selected from 28 bottles by 28C6 ways .

28C6 = 28! / ((28-6)! * 6!) = 376740

c)

If 6 bottles are randomly selected, number of ways to obtain 2 bottles of each veriety is

9C2 * 8C2 * 11C2

= 55440

d)

P( 2 bottles of each veriety ) = n( 2 bottles of each veriety ) / n(choosing 6 bottles from 28)

= 9C2 * 8C2 * 11C2 / 28C6

= 55440 / 376740

= 0.147

e)

P(All 6 bottles of same veriety) = P(all 6 bottles of zinfandel from 9) + P(all 6 bottles of merlot from 8) +   

P( all 6 bottles of cabernet from 11) / P( 6 bottles from 28 )

= ( 9C6 + 8C6 + 11C6 )/ 28C6

= 574 / 376740

= 0.002

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